Optimal. Leaf size=64 \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}-\frac{a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \tanh ^{-1}(\sin (c+d x))}{4 d} \]
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Rubi [A] time = 0.0869577, antiderivative size = 64, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {2836, 12, 77, 206} \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}-\frac{a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \tanh ^{-1}(\sin (c+d x))}{4 d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 77
Rule 206
Rubi steps
\begin{align*} \int \sec ^4(c+d x) (a+a \sin (c+d x))^2 \tan (c+d x) \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{x}{a (a-x)^3 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^4 \operatorname{Subst}\left (\int \frac{x}{(a-x)^3 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^4 \operatorname{Subst}\left (\int \left (\frac{1}{2 (a-x)^3}-\frac{1}{4 a (a-x)^2}-\frac{1}{4 a \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^4}{4 d (a-a \sin (c+d x))^2}-\frac{a^3}{4 d (a-a \sin (c+d x))}-\frac{a^3 \operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{4 d}\\ &=-\frac{a^2 \tanh ^{-1}(\sin (c+d x))}{4 d}+\frac{a^4}{4 d (a-a \sin (c+d x))^2}-\frac{a^3}{4 d (a-a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 0.0800397, size = 36, normalized size = 0.56 \[ -\frac{a^2 \left (\tanh ^{-1}(\sin (c+d x))-\frac{\sin (c+d x)}{(\sin (c+d x)-1)^2}\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.067, size = 126, normalized size = 2. \begin{align*}{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}{a}^{2}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{a}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{a}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{{a}^{2}\sin \left ( dx+c \right ) }{4\,d}}-{\frac{{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{4\,d}}+{\frac{{a}^{2}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.15226, size = 86, normalized size = 1.34 \begin{align*} -\frac{a^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - a^{2} \log \left (\sin \left (d x + c\right ) - 1\right ) - \frac{2 \, a^{2} \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right ) + 1}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.51917, size = 297, normalized size = 4.64 \begin{align*} -\frac{2 \, a^{2} \sin \left (d x + c\right ) +{\left (a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} \sin \left (d x + c\right ) - 2 \, a^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} \sin \left (d x + c\right ) - 2 \, a^{2}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right )}{8 \,{\left (d \cos \left (d x + c\right )^{2} + 2 \, d \sin \left (d x + c\right ) - 2 \, d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22033, size = 128, normalized size = 2. \begin{align*} -\frac{a^{2} \log \left ({\left | \frac{1}{\sin \left (d x + c\right )} + \sin \left (d x + c\right ) + 2 \right |}\right ) - a^{2} \log \left ({\left | \frac{1}{\sin \left (d x + c\right )} + \sin \left (d x + c\right ) - 2 \right |}\right ) + \frac{a^{2}{\left (\frac{1}{\sin \left (d x + c\right )} + \sin \left (d x + c\right )\right )} - 6 \, a^{2}}{\frac{1}{\sin \left (d x + c\right )} + \sin \left (d x + c\right ) - 2}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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